Minimum possible largest element after k operations. e, arr [i]), K times.

Minimum possible largest element after k operations. By incrementing the smallest value, we are effectively leveling the array and minimizing the maximum value that will result after k operations. Jul 23, 2025 · Naive Approach: This problem can be solved by checking for the possibility of maximum possible minimum value from [1, max (array)] by performing the operations from the end of the array. Mar 9, 2024 · This code snippet first identifies the index of the minimum value in the array and increments it by one. - hogan-tech/leetcode-so You can perform at most k operations total. Jul 23, 2025 · isMaximum (mid) function used to check whether mid can be largest value of array after performing given operations. Ideal for interview prep, learning, and code practice in multiple programming languages. Example 1: Input: nums = [2,8,3,19,3], k = 3, op1 = 1, op2 = 1 Output: 23 Explanation: * Apply Operation 2 to nums [1] = 8, making nums [1] = 5. In-depth solution and explanation for LeetCode 2530. Return the minimum possible value of the maximum integer of nums after performing any number of operations . Better than official and forum solutions. * Rearrange the elements of arr to be in any order. Intuitions, example walk through, and complexity analysis. It repeats this k times. Aug 13, 2025 · K = 6 In the first step, we will multiply the element 1 with 6, and the elements will become 6. Return the minimum possible sum of all elements in nums after performing any number of operations. Return *the maximum possible score you can attain after applying exactly* k operations. Return the maximum possible score you can attain after applying exactly k operations. The ceiling function ceil(val) is the least integer greater than or equal to val. Return an integer corresponding to the minimum possible largest element after K operations. k and all numbers in array num > 1. Perform B operations in such a way that the largest element of the modified array (after B operations) is minimised. e, arr [i]), K times. Your goal is to find the maximum possible frequency of any element after performing at most k operations. You can choose any of the elements in each operation. Jul 15, 2025 · Given an array of integers arr [] consisting of N integers, the task is to minimize the sum of the given array by performing at most K operations, where each operation involves reducing an array element arr [i] to floor (arr [i]/2). N = 3 A [] = {1, 5000, 9999} K = 10000 Jul 23, 2025 · For each element in the array, calculates the minimum number of operations needed to make that element at least mid. So the minimum difference between the minimum and the maximum element will be equal to 10 - 2 = 8. Now for the last operation, either you can pop one more element, or can push one element from the popped elements. Maximal Score After Applying K Operations in Python, Java, C++ and more. Note: Both operations can be applied to the same index, but at most once each. Aug 5, 2018 · Pop k-1 elements in k-1 operations. Jul 23, 2025 · Given an array arr [] of size N and a positive integer K, the task is to find the maximum difference between the largest element and the smallest element in the array by incrementing or decrementing array elements by that element itself (i. Can you solve this real interview question? Minimize Maximum of Array - You are given a 0-indexed array nums comprising of n non-negative integers. So, our answer will be 8. If the total number of operations used is less than or equal to K, it’s possible to make all elements at least mid. For example, if nums = [1, 2, 4] and k = 5, you could increment the first element three times (1→2→3→4) and the second element twice (2→3→4), using all 5 operations. Since the top element of the min-heap is the smallest among the k elements, if the current element is larger than the top, it means the top element is no longer one of the k largest elements. In this case, we remove the top and insert the larger element. In one operation, you must: * Choose an integer i such that 1 <= i < n and nums[i] > 0. There are 2 types of operations that you can perform any number of times: * Decrease the value of any element of arr to a smaller positive integer. Perform the operations in such a way the largest element of the modified array (after operations) is minimised. The m For each test case, you need to print an integer that represents the minimum possible largest element after K operations. Explore diverse LeetCode solutions in Python, C++, JavaScript, SQL, and TypeScript. The minimum element will be 2, and the maximum will be 10 after this operation. So compare both the cases, if you pop element in kth operation, the element on top should be more than all first k-1 popped elements, otherwise for kth operation push the largest element from k-1 popped elements. I need to find its minimum sum after these k manipulations. Feb 26, 2019 · An array is manipulated k times so that each time the max value is devided by 2 and rounded up. * Decrease nums[i] by 1. * Increase nums[i - 1] by 1. Jul 23, 2025 · After that, for each next element, we compare it with the top of the heap. aj ed14 sep8 fmne vffrogq rj63p rsc adomjx 2sukozb9 3rk9z